re = /(([0-3]\d)\/(0[4-9]|1[012]))\/1999/m
str = '01/03/1999 too early
30/03/1999 too early
01/04/1999
31/04/1999 invalid date (month-specific)
35/04/1999 invalid date
30/05/1999
31/05/1999'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html