import Foundation
// WARNING: You included a flag that Swift doesn't support: u
// When this flag is set, it makes the pattern and subject strings to be treated as unicode.
// Swift already treats the pattern and subject strings as unicode by default, so including this flag is redundant.
let pattern = #"^\d{1,5}[-\p{L}][-\p{L}\d]{0,9}$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
12345a235
123a
12345-aa1
12345a
12345-a
12-a235dkfsf
12-a235dkfsfs
123a-dssava-y
123a-dssava-1a
12345-aa1--asd-
12345-aa1--asd-s
-11
111111
aaaa
version 1 :: plain ... ^\d{1,5}[-\p{L}][-\p{L}\d]{0,9}$
version 2 :: named ... ^(?<digitsOnly>\p{N}{1,5})(?<miscellaneous>[-\p{L}][-\p{L}\p{N}]{0,9})$
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression