import re
regex = re.compile(r"^(?:((?P<p1>(?:\( ?)?+)(?:\+|00)?(54)(?<p2>(?: ?\))?+)(?P<sep>(?:[-.]| (?:[-.] )?)?+)(?:(?&p1)(9)(?&p2)(?&sep))?|(?&p1)(0)(?&p2)(?&sep))?+(?&p1)(11|([23]\d{2}(\d)??|(?(-10)(?(-5)(?!)|[68]\d{2})|(?!))))(?&p2)(?&sep)(?(-5)|(?&p1)(15)(?&p2)(?&sep))?(?:([3-6])(?&sep)|([12789]))(\d(?(-5)|\d(?(-6)|\d)))(?&sep)(\d{4})|(1\d{2}|911))$", flags=re.MULTILINE)
test_str = ("+54 11 4444-0000\n"
"+54 341 1118888\n"
"(+549261)1234567\n"
"(0351)333-4444\n"
"266 - 999 - 0000\n"
"343-1238888\n"
"+5491188884444\n"
"543412228888\n"
"(54)233-15-111-2222\n"
"(+54-343)9990000\n"
"+54 (3436) 99-0000\n"
"(0)8003337333\n"
"11-4-9876543\n"
"+54 11(4444)0000\n"
"+54 341 1111-888\n"
"(+54261)12-34567\n"
"(03510)3334444\n"
"266-99-0000\n"
"4444-5555\n"
"34-5555-0000\n"
"444-5555")
matches = regex.finditer(test_str)
for match_num, match in enumerate(matches, start=1):
print(f"Match {match_num} was found at {match.start()}-{match.end()}: {match.group()}")
for group_num, group in enumerate(match.groups(), start=1):
print(f"Group {group_num} found at {match.start(group_num)}-{match.end(group_num)}: {group}")
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html