import Foundation
let pattern = #"^(?:((?P<p1>(?:\( ?)?+)(?:\+|00)?(54)(?<p2>(?: ?\))?+)(?P<sep>(?:[-.]| (?:[-.] )?)?+)(?:(?&p1)(9)(?&p2)(?&sep))?|(?&p1)(0)(?&p2)(?&sep))?+(?&p1)(11|([23]\d{2}(\d)??|(?(-10)(?(-5)(?!)|[68]\d{2})|(?!))))(?&p2)(?&sep)(?(-5)|(?&p1)(15)(?&p2)(?&sep))?(?:([3-6])(?&sep)|([12789]))(\d(?(-5)|\d(?(-6)|\d)))(?&sep)(\d{4})|(1\d{2}|911))$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
+54 11 4444-0000
+54 341 1118888
(+549261)1234567
(0351)333-4444
266 - 999 - 0000
343-1238888
+5491188884444
543412228888
(54)233-15-111-2222
(+54-343)9990000
+54 (3436) 99-0000
(0)8003337333
11-4-9876543
+54 11(4444)0000
+54 341 1111-888
(+54261)12-34567
(03510)3334444
266-99-0000
4444-5555
34-5555-0000
444-5555
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression