import Foundation
let pattern = #"^[^\S\n]*(\S+)[^\S\n]{2,}([\d,]+)[^\S\n]{2,}(\S+)[^\S\n]{2,}(\d+)[^\S\n]{2,}(\S+)[^\S\n]{2,}(\S+)[^\S\n]{2,}(up|down)+[^\S\n]{2,}(up|down)+[^\S\n]{2,}([\w +?]+)[^\S\n]{2,}(\S+)"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
admin@str-s6000-on-5:~$ show interface status Ethernet4
Interface Lanes Speed MTU Alias Vlan Oper Admin Type Asym PFC
--------------- ----------- ------- ----- ------------ ------ ------ ------- -------------- ----------
Ethernet4 29,30,31,32 40G 9100 fortyGigE0/4 trunk up up QSFP+ or later off
PortChannel0001 N/A 40G 9100 N/A routed up up N/A N/A
PortChannel0002 N/A 40G 9100 N/A routed up up N/A N/A
PortChannel0003 N/A 40G 9100 N/A routed up up N/A N/A
PortChannel0004 N/A 40G 9100 N/A routed up up N/A N/A
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression