import Foundation
let pattern = #"(Order[0-9])(?!.*\1)"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
<ctx>
<PostCode>XXXXXX</PostCode>
<Title1>Mr</Title1>
<Name>John</Name>
<Order1>£100.00</Order1>
<Order2>£100.01</Order2>
<Order3>£100.01</Order3>
<Order4>£100.01</Order4>
<Order5>£100.01</Order5>
<Order6>£100.01</Order6>
<Order7>£100.01</Order7>
<Order8>£100.01</Order8>
<Order9>£100.01</Order9>
<Order10>£100.01</Order10>
<Order11>£100.01</Order11>
<Order50>£100.01</Order50>
<Date>10/10/2010</Date>
</ctx>
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression