re = /^\d{2}(0[1-9]|1[012])(0[1-9]|[12][0-9]|3[01])\d{6}$/m
str = '190131958103
201331958103
190100958103
190132958103
190031958103
441201485383
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html