import Foundation
let pattern = #"<table\b[^\>]*\bname=(\"|')?table01\1[^\>]*>(?>([^\<]+|<(?!\/?table\b))|(<table[^\>]*>(?:(?2)|(?3)|)+?<\/table>))*<\/table>"#
let regex = try! NSRegularExpression(pattern: pattern, options: [.caseInsensitive, .allowCommentsAndWhitespace])
let testString = #"""
<table name="table01" data-measure-unit="Y">
<table></table>
</table>
<table name="table01" data-measure-unit="Y">
<div>
<table></table>
</div>
</table>
<table name="table01" data-measure-unit="Y">
<div>
<table>
<table>
</table>
</table>
</div>
</table>
<table name="table01" data-measure-unit="Y">
<div>
<div></div>
</div>
</table>
<table name="table01" data-measure-unit="Y">
</table>
<table name="table01"></table>
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression