re = /^(?!0\d*$)\d+(?:\.\d{1,2})?$/m
str = 'These are the scenarios that we can accept:
0.01
1.1
1.02
120.01
We can\'t accept these values
0023
0100
.01
.12
001.02
0000'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html