using System;
using System.Text.RegularExpressions;
public class Example
{
public static void Main()
{
string pattern = @"\b(?>1(?:01)*0?|0(?:10)*1?)\b";
string input = @"no binary numbers here 3434.
Hey friend this is a 1.
Those are 1001, 1010, 1011, 1100, 1101
This is a long value 10101010101 and this one as well 1010101010101011
0 + 0 is a also a 0.
1";
foreach (Match m in Regex.Matches(input, pattern))
{
Console.WriteLine("'{0}' found at index {1}.", m.Value, m.Index);
}
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for C#, please visit: https://msdn.microsoft.com/en-us/library/system.text.regularexpressions.regex(v=vs.110).aspx