# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility
import re
regex = r"\s*\b\d+\b\s*"
test_str = ("0 I64 EB MM 93\n"
"1519 KINGSCROSS RD\n"
"28 VA288 298\n"
"JOHN RANDOLPH RD\n"
"4700 WALMSLEY BL\n"
"BOWLING GREEN RD / BOB WHITE RD\n"
"BRUCE CT /FLORIDA AV\n"
"BUCK RD AND WHITEHALL RD\n"
"DOWNTOWN EWRESSWY EB 2ND ST\n"
"HYHLAND VISTA / GEORGE WASHINGTON BL\n"
"HYHLAND VISTA / GEORGE WASHINGTON BL\n"
"HYHLAND VISTA DR / GEORGE WASHINGTON BL\n"
"I95 25 43\n"
"LAUARL RIDGE MILL RD /CLARENCE RD\n"
"LAUARL RIDGE MILL RD /CLARENCE RD\n"
"NOVAH HOWARD ST /SEMINARY RD\n"
"OLD COUVAHOUSE RD R COUVAHOUSE RD\n"
"OLD COUVAHOUSE RD R COUVAHOUSE RD\n"
"WOODLAND AND ROANOKE\n"
"1501 SAMS CR1\n"
"15281 WHITEHEAD RD\n"
"1532 MARLBORO ST\n"
"16907 BRANDERS BRIDGE RD\n"
"1750 WILLIAM ST")
subst = ""
# You can manually specify the number of replacements by changing the 4th argument
result = re.sub(regex, subst, test_str, 0, re.MULTILINE)
if result:
print (result)
# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html