re = /\b((?:\d{4}\ ){3}\d{4}|\d{16})\b/m
str = '1234 4567 1234 4567
1234456712344567
12344567 1234 4567
12344567123445678'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html