re = /([a-zA-Z]|\s|^)((\+84|0)(1[2689]|9)+[0-9]{8})([a-zA-Z]|\s|$)/
str = '0989914009 nguyeng quangthang0989914009 thang 9301234567898 123 01201234567892 0989914009 nguyeng quang nn thang +84989914009
nmv nguyeng quang thang0989914009'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html