import Foundation
let pattern = #"([(-.+]*+[0-9]+[()-.+ ]*+[0-9]+[()-.+ ]*+[0-9]+[()-.+ ]*+[0-9]+[()-.+ ]*+[0-9]+[()-.+ ]*+[0-9]+[()-.+ ]*+[0-9]+[()-.+ ]*+[0-9]*+[()-.+ ]*+[0-9]*+[()-.+ ]*+[0-9]*+[()-.+ ]*+[0-9]*+)"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
Lorem ipsum foo@bar.com dolor sit amet, 555 123555 consectetur adipiscing elit.
Here (works) 0606060606 (not works) 06.06.06.0.06.06 06.06 ... .06.06.06 price is 20. 000.000
555.123.4565
+1-(800)-545-2468
+ 1 -(800)-545-2468
2-(800)-545-2468
3-800-545-2468
555-123-3456
555 222 3342
(234) 234 2442
(243)-234-2342
1234567890
123.456.7890
123.4567
123-4567
1234567900
12345678900
+8.4.0.9.6.6.4.3.0.0.9
my price is only 20$, 2000$
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression