re = /^(0[1-9]|[12][0-9]|3[01])(\/|-)?(0[1-9]|1[012])(((\/)?([0-9]{4}|[0-9]{2}))|((\/|-)?[0-9]{4}))$/m
str = '13/10/2022
10/10/2022
13/10/22
10/10/22
13-10-2022
10-10-2022
13-10-22
10-10-22
131022
101022
13102022
10102022
20221013
20221010
2022-10-13
2022-10-10
2022/10/13
2022/10/10'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html