re = /[:*\n]/
str = 'Languages: JAVA (2 years), Python (6 months), C (1 year), C++
Web Technologies: HTML, CSS3, PHP, JavaScript, JQuery, AJAX, Bootstrap, WordPress, JSP, Servlets, HTTP, XML, JSON
Databases: MySQL, PostgreSQL Amazon RDS, Dynamo DB, Google Cloud Datastore, SQL expert, NoSQL
Frameworks: Flask, SQL-Alchemy, Hive, JPA, Hibernate, Weka, NumPy, Pandas
Tools/Technology: Eclipse, PyCharm, Docker, AWS, Terminal, Unix Scripting, Tomcat, Maven, GIT, SVN, Arduino, PIC
'
subst = ','
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html