import Foundation
let pattern = #"^(\w{3}\s{1}\w{3}\s{1}\d{2}\s{1}\d{2}\:\d{2}\:\d{2}\s{1}\d{4})?((\r||.|\n)*)(?=(\w{3}\s{1}\w{3}\s{1}\d{2}\s{1}\d{2}\:\d{2}\:\d{2}\s{1}\d{4}))"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = ##"""
Tue Sep 14 08:57:47 2021
Thread 1 advanced to log sequence 186 (LGWR switch)
Current log# 2 seq# 186 mem# 0: D:\ORADB\DV1\REDO02A.LOG
Current log# 2 seq# 186 mem# 1: H:\ORADB\DV1\REDO02B.LOG
Tue Sep 14 09:07:40 2021
Thread 1 advanced to log sequence 187 (LGWR switch)
Current log# 3 seq# 187 mem# 0: D:\ORADB\DV1\REDO03A.LOG
Current log# 3 seq# 187 mem# 1: H:\ORADB\DV1\REDO03B.LOG
Tue Sep 14 09:22:09 2021
Thread 1 advanced to log sequence 188 (LGWR switch)
Current log# 4 seq# 188 mem# 0: D:\ORADB\DV1\REDO04A.LOG
Current log# 4 seq# 188 mem# 1: H:\ORADB\DV1\REDO04B.LOG
Tue Sep 14 09:38:03 2021
Thread 1 advanced to log sequence 189 (LGWR switch)
Current log# 1 seq# 189 mem# 0: D:\ORADB\DV1\REDO01A.LOG
Current log# 1 seq# 189 mem# 1: H:\ORADB\DV1\REDO01B.LOG
"""##
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression