re = /\b(?:Name|Age):\h*((?:.(?!(?:Name|Age):))+)/m
str = 'fhsdgjfsdk;snfd fsd ;lknf;ksld sldkfj lk
Name: Max Pain
Age: 99 Years
and they df;ml dk fdj,nbfdlkn ......
fhsdgjfsdk;snfd fsd ;lknf;ksld sldkfj lk
Name: Max Pain Age: 99 Years
and they df;ml dk fdj,nbfdlkn ......'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html