re = /^(?=(?<http>(?:https?:\/\/){1}(?:www\.)?)?)(?(?=\k<http>?(?<ipaddr>(?:\d{1,3}\.){3}\d{1,3}(?:\:\d{1,5})?))\k<http>?\k<ipaddr>(?:\.[\w]{1,9})?|\k<http>(?:[\w]\.?){1,255}\.[\w]{1,9})(?:\/.*)?$/m
str = 'https://www.bt.dk/forbrug/salling-group-vil-udnytte-vild-hype-med-populaer-drikkevare
10.135.153.16.dk
https://10.135.154.16.dk
https://10.135.153.16:5000.dk
10.135.153.12:5000.dk
1.1.1.1.dk
1.1.1.1:5000.dk
https10.135.153.16.dk
https://.example.com
https://example
ftp://www.example.com
https://www example.com
htt://www.example.com
https://git.pcsyd.dk
wwwjek.dk
https://100.100.100.100.dk
https://100..100.10.100.dk'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html