re = /\bsection \d+ (?:(?!\bsection \d+).)*?(?:19|20)\d{2}\b/m
str = 'section 1 bar bar section 2 foo 2019 foo section 3 bar 2021 bar end'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html