re = /(2014)(.*?baloon.*)(?:2014)/mi
str = '2014.10.30: b
l
ah bl
a
h
2014.10.30: bfoo
lah
b
l
ah
2014.10.30: bart1
lah
baloon
l
ah
2014.10.30: carb
lah
b
l
ah
2014.10.30: farb2
lah
baloon
l
ah
2014.10.30: carb
lah
b
l
ah
2014.10.30: bom
lah
baloob
l
ah
etc'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html