import Foundation
let pattern = #"^((?=[0-9.]+$)((25[0-5]|(2[0-4]|1[0-9])[0-9]|[1-9]?[0-9])\.){3}(25[0-5]|(2[0-4]|1[0-9])[0-9]|[1-9]?[0-9])|(?=[0-9.]*[a-zA-Z])([a-zA-Z0-9]|[a-zA-Z0-9][a-zA-Z0-9-]{0,61}[a-zA-Z0-9])((\.([a-zA-Z0-9]|[a-zA-Z0-9][a-zA-Z0-9-]{0,61}[a-zA-Z0-9]))*(\.[a-zA-Z]{2,31}))+)$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
127.0.0.1
192.168.1.1
192.168.1.255
192.168.255.255
0.0.0.0
127.0.0.1
192.168.1.1a
192.068.1.255
30.168.1.255.1
127.1
192.168.1.256
-1.2.3.4
1.1.1.1.
3...3
toto.fr
truc-bidule.com
sub.truc-bidule.toto.com
toto
toto.f
toto.f6
-3.fr
toto.fr
truc_bidule.com
sub..truc-bidule.toto.com
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression