re = /((\d)(?!\2{3})){16}/
str = '5123456789123456
6123456789123456
4123356789123456
5133336789123456
1234567890134443'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html