using System;
using System.Text.RegularExpressions;
public class Example
{
public static void Main()
{
string pattern = @".*\s(?<Memory>.\d*)\s(?<Cpu>.\d*)\s(?<Truc>[^\s+]*)";
string substitution = @"";
string input = @"20160607-10:27:01 427369444501 14445 2.9788888 37.1";
Regex regex = new Regex(pattern);
string result = regex.Replace(input, substitution, 1);
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for C#, please visit: https://msdn.microsoft.com/en-us/library/system.text.regularexpressions.regex(v=vs.110).aspx