re = /(?!.+(\bgoogle.com\b))(<a[^>]+href=")(http|https)([^>" ]+)("?[^>]*>)/m
str = '<a href="http://www.google.com">google</a>
<a href="http://www.exmple.com">example</a>
<a href="http://www.google.com">google</a>
<a href="http://www.exmple.com">example</a>'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html