# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility
import re
regex = (r"(?x) #ignora isso é para aceitar multi linha e comentario\n\n"
r"^ # inicio\n"
r"(?=.*?[a-z]) # procura por caracteres `a` atá `z` pelo menos 1\n"
r"(?=(?:.*?\d){9}) # procura por 9 digitos \n"
r"[a-z\d ]{12,} # tem que ter 12 digitos ou mais entre `a` e `z` numeros e espaços\n\n"
r"$ # fim\n")
test_str = ("aeioa123rasdaer12311412s\n"
"a 1 2 3 4 a f e 4 6 9 a 1 2\n"
"falha Por Que so tem Letras e espaço\n"
"012345679PassaPorqueTemNumeros\n"
"444Pass4 3P0r que T3m L3tr4as numeros e espaco \n"
"012345678901")
matches = re.finditer(regex, test_str, re.MULTILINE | re.IGNORECASE)
for matchNum, match in enumerate(matches, start=1):
print ("Match {matchNum} was found at {start}-{end}: {match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group()))
for groupNum in range(0, len(match.groups())):
groupNum = groupNum + 1
print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = match.start(groupNum), end = match.end(groupNum), group = match.group(groupNum)))
# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html