use strict;
my $str = 'How to write regex which find word (without whitespace) that doesn\'t contain some chars (like * or #) and sentence also (like level10 or level2 - it should be also regex - level[0-9]+). It will be simple for chars excluded ([^\\\\s^#^*]+) but how to exclude this \'level\' example too ?
I want to exclude chars AND level with number.
Examples:
weesdlevel3fv - shouldn\'t match because of \'level3\'
we3rlevelw4erw - should match - there is level without number
dfs3leveldfvws#3vd - shouldn\'t match - level is good, but \'#\' char appeared
level4#level levelw4_level - threat as two words because of whitespaces - only second one should match - no levels with number and no restricted chars like \'#\' or \'*\'';
my $regex = qr/(?<=\s)(?!\S*level[0-9])[^\s#*]+(?=\s)/p;
if ( $str =~ /$regex/g ) {
print "Whole match is ${^MATCH} and its start/end positions can be obtained via \$-[0] and \$+[0]\n";
# print "Capture Group 1 is $1 and its start/end positions can be obtained via \$-[1] and \$+[1]\n";
# print "Capture Group 2 is $2 ... and so on\n";
}
# ${^POSTMATCH} and ${^PREMATCH} are also available with the use of '/p'
# Named capture groups can be called via $+{name}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Perl, please visit: http://perldoc.perl.org/perlre.html