re = /(a)?b(?(1)c|d)/m
str = 'matches bd and abc. It does not match bc, but does match bd in abd. Let\'s see how this regular expression works on each of these four subject strings.
If-Then-Else Conditionals in Regular Expressions
http://www.regular-expressions.info/conditional.html'
subst = '\\1'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html