re = /^((?:\S+\s+){4})/m
str = 'EE84 1484.74 1364.99 62.5 2 1 0 1
EE85 505.23 841.63 60. 2 1 0 1
EE86 945.95 913.39 100. 1 0 0 0
P3 972.44 1126.12 100. 1 0 0 0
P28 980.0 1119.0 100. 1 0 0 0
P100 964.03 1125.93 100. 1 0 0 0
P102 963.49 1133.71 100. 1 0 0 0
P106 974.06 1150.73 100. 1 0 0 0
P108 1017.36 1062.47 100. 1 0 0 0
P109 965.31 1151.14 100. 1 0 0 0 '
subst = '${1}0 '
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html