re = /4(\.|,)*(b|!|8)*\.?\s*[0-9\.]*/
str = 'OCR: B VOZAGKA DOZVOLA REPURLKAHRWISGA )
HR 1. UZORAK
2. SPECIMEN
3. 01011977
1 42.01.07.2013 4. PUDUBROVACKO - NERETVANSKA
e 4b. 01.07.2023
5. 1234587 S i
, E %I\\\\\'\\f Dt — |
: = L 9.8 =
D112345671234567890121012017<2'
# Print the match result
str.match(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html