re = /^\d{0,8}?(\.)?(\d{1,2})?$/m
str = '
0
123
1234567890
12345678901
1234.
0.
1234567890.12
1234567890.123
.1
.12
.123
.
123.123
123.12
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html