re = /(0(?!0)|[1-2]|3(?=[0-1]))\d\/(0(?!0)|1(?=[0-2]))\d\/\d{4}/
str = ' some matched dates (DD/MM/YYYY): 33/18/2005 31/01/2009
basic check for month/day boundaries: 33/02/2005 12/18/2007
NO check for month specific boundary: 31/22/2009
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html