using System;
using System.Text.RegularExpressions;
public class Example
{
public static void Main()
{
string pattern = @"^(?!(192\.168\.))^(?!(172\.(1[6-9]|2[0-9]|3[0-1])\.))^((([1-9]|1[1-9]|[2-9][0-9]|1[0-9]{2}|2[0-1][0-9]|22[0-3])\.)((0|1[0-9]{0,2}|[2-9][0-9]|2[0-4][0-9]|25[0-5])\.){2}(1[0-9]{0,2}|[2-9][0-9]|2[0-4][0-9]|25[0-4]))$";
string input = @"0.0.0.0
1.0.0.0
1.0.0.1
01.0.0.1
1.00.0.1
1.0.00.1
1.0.0.01
1.0.0.254
1.0.0.255
10.0.0.1
11.0.0.1
11.20.0.1
11.99.0.1
11.100.0.1
172.15.255.254
172.16.0.1
172.19.254.254
172.31.255.254
172.32.0.1
192.168.0.1
192.169.0.1
223.0.0.1
223.255.255.254
223.255.255.255
224.0.0.1
255.0.0.0
255.0.0.1
255.255.0.1
";
RegexOptions options = RegexOptions.Multiline;
foreach (Match m in Regex.Matches(input, pattern, options))
{
Console.WriteLine("'{0}' found at index {1}.", m.Value, m.Index);
}
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for C#, please visit: https://msdn.microsoft.com/en-us/library/system.text.regularexpressions.regex(v=vs.110).aspx