re = /^(?:\d{1,13}(?:\.\d{1,2})?|\.[1-9][0-9]?)$/m
str = '0
0.5
1.55
.5
1234567890123
1234567890123.5
1234567890123.00
.01
.
.,
.0
1.234
5.
12345678901234
12345678901234.56
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html