re = /(\b10\.5\.(29|31|32)\.15\b|\b10\.0\.100\.75\b)/
str = '10.5.31.15
45.36.87.12
10.0.100.75
192.168.1.168
10.5.4.15
10.5.32.15
10.10.25.36
10.0.100.56
10.5.29.15'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html