re = /(?: 0(?=1|\b)| 1(?=2|\b)| 2(?=3|\b)| 3(?=4|\b)| 4(?=5|\b)| 5(?=6|\b)| 6(?=7|\b)| 7(?=8|\b)| 8(?=9|\b)| 9\b ){5}/x
str = '123 321 56789 890123 321098 134 333 421 12345 6789
15246
1234567890
67890
12345
23456
34567
456789
56789
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html