re = /^(?:(?=.{1,10}$)\d{1,3}(?:,\d{3})+|(?=.{1,8}$)\d+)$/m
str = '20
3000
4,000
600000
7,000,000
8000000
7,00
9,99
9,999
6,000,000
987654
2000,000
99999999
999999999
99,999,999
999,999,999'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html