import Foundation
let pattern = #"""
(
(\d+|pi|\\u03C0|\\u03A0|phi|\\u03C6|\\u03A6)
|
(abs|acos|cos|atan|tan|asin|sin|ceil|floor|sqrt|log|ln)\([^)]+\)
)
(
\s*([+\-*\/^]|mod)\s*
(
(\d+|pi|\\u03C0|\\u03A0|phi|\\u03C6|\\u03A6)
|
(abs|acos|cos|atan|tan|asin|sin|ceil|floor|sqrt|log|ln)\([^)]+\)
)
)*
\s*=
"""#
let regex = try! NSRegularExpression(pattern: pattern, options: .allowCommentsAndWhitespace)
let testString = #"""
test text (1) pi=
test text (1 pi=
test text 1) pi=
test text (2) pi + 10 / 20=
test text (3) test pi ^ 10 / 20=
test text (30) 10 + 5=
test text (500) abs(10 + 5)=
test text (1) pi + 10 / 20=
test text 10*5=
test text pi / phi=
test text 10 mod phi=
test text 50 10 mod phi=
test text pi mod abs(phi)=
apple banana cherry apple 10 apple cherry banana hi 10 99+1=
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression