re = /p([1]?[0-9]|20)\.b([1]?[0-9]|20)\.val/m
str = 'p20.b18.val
p3.b4.val
p.b.val
p3.b1.val'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html