using System;
using System.Text.RegularExpressions;
public class Example
{
public static void Main()
{
string pattern = @"\b@[\d.]*\d";
string input = @"jsesc@1.3.0 [license(s): MIT]
package.json: MIT
json-schema@0.2.3 [license(s): AFLv2.1, AFLv2.1/BSD, BSD]
package.json: AFLv2.1, AFLv2.1/BSD, BSD
readme files: BSD
json-schema-traverse@0.3.1 [license(s): MIT]
package.json: MIT
license files: MIT
json-stable-stringify@1.0.1 [license(s): MIT]
package.json: MIT
license files: MIT
readme files: MIT
json-stringify-safe@5.0.1 [license(s): ISC]
package.json: ISC
license files: ISC
json5@0.4.0 [license(s): MIT]
package.json: MIT
readme files: MIT
json5@0.5.1 [license(s): MIT]
package.json: MIT
license files: MIT";
foreach (Match m in Regex.Matches(input, pattern))
{
Console.WriteLine("'{0}' found at index {1}.", m.Value, m.Index);
}
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for C#, please visit: https://msdn.microsoft.com/en-us/library/system.text.regularexpressions.regex(v=vs.110).aspx