re = /\b(?:2\d(?:1[4-9]|[2-9]\d)|\d{5,}|[3-9]\d{3,})\b/
str = '1999 1985 2013 2014 2007 2016 2050 18075 12370 2199 2267 9999 3000 4000 4211'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html