import Foundation
let pattern = #"@(\"[\w\s-]+\")|(?!@([\w-]+)@([\w-]+))@([\w-]+)"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
There is @key-1 apples on the table.
There is @"key1" apples on the table.
There is @key 4 apples on the table.
There is @"key 4" apples on the table.
There is @key@key2 apples on the table.
There is @key3 apples on the table. (second step)
There is @"key @"key3"" apples on the table.
There is @"key 4" apples on the table. (second step)
There is @"key @key3" apples on the table.
There is @"key 4" apples on the table. (second step)
There is @"key @key3 " apples on the table.
There is @"key 4 " apples on the table. (second step)
There is @"key-@"key-3@key7"" apples on the table.
There is @"key-@"key-32"" apples on the table. (second step)
There is @"key-21" apples on the table. (3rd step)
There is @key@key2@key3@key4 apples on the table.
There is @key@key2@key35 apples on the table. (second step)
There is @key@key26 apples on the table. (3rd step)
There is @key7 apples on the table. (4th step)
There is @key-5 apples on the table.
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression