re = /^L([0-9a-zA-Z]+)S([0-9a-zA-Z]+)/m
str = '12345
L12345
L1S1
LS1
L123S45
L1x23S4yZY5
L1x!23S4y5'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html