use strict;
my $str = '2day-2023-1-5--20-0.csv
1day-2023-2-5--20-0.csv
3day-2021-1-5--20-0.csv
103day-2021-1-5--20-0.csv';
my $regex = qr/\d+day-(\d{4}-\d{1,2}-\d{1,2})--.*/mp;
my $subst = '\\1';
my $result = $str =~ s/$regex/$subst/rg;
print "The result of the substitution is' $result\n";
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Perl, please visit: http://perldoc.perl.org/perlre.html