re = /^( *)(if(.|\n)+?^(?!\1 |#|\1el|\n))/m
str = 'if aaa=1:
# dfdf fdf
xxx
if cc = 4:
rrr
else:
ww
if aaaaa:
# dssfdsf
ttt
elif bb=2:
if ll is True:
return
yyy
else:
zzz
dfsdfsaa'
subst = '\\1\\2\\1# endif\\n'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html