re = /^((0[1-9]|[12]\d|3[01])-(0[1-9]|1[0-2])-[12]\d{3} (0[0-9]|1[0-9]|2[1-4]):(0[0-9]|[1-5][0-9]):(0[0-9]|[1-5][0-9]))$/m
str = '10-12-2022 23:59:59
10-22-2022 2:59:59
10-12-2022 02:59:99
10-12-2022 02:59:59
00-12-2022 02:59:59
10-22-2022 02:59:59
10-12-2022 025959
// You can show origina post on albertcolom.com/blog'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html