re = /(\d+)\^(?:\d+\^)*a/
str = '1^1^4~3^4^2~4^9^a
4^2^2~8^9^a~1^1^1 '
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html