re = /^(?!0\d)\d{1,3}(?:\.\d{3})*,\d{2}$/m
str = '1.123,45
1,23
1.234.567,45
0,56
0,00
12
01,56
1,5
01,100.36
1,1236.25'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html