import Foundation
let pattern = #"^(?:(?:10\.\d{1,3}\.\d{1,3}\.\d{1,3}|172\.(?:(?:1[6-9])|(?:2[0-9])|(?:3[0-1]))\.\d{1,3}\.\d{1,3}|192\.168\.\d{1,3}\.\d{1,3}|127\.\d{1,3}\.\d{1,3}\.\d{1,3})(?::\d{1,5})?)$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
127.0.0.1
127.255.255.255
127.0.0.1:3000
10.0.0.1
10.0.0.2
10.0.1.1
10.0.1.2:443
172.16.0.1
172.16.0.2
172.16.1.1
172.16.1.2
192.168.0.1
192.168.0.2
192.168.1.1
192.168.1.2
10.10.10.1
10.10.10.2
172.31.255.1
172.31.255.2
192.168.100.1
192.168.100.2
10.255.255.1
10.255.255.2
8.8.8.8:80
1.1.1.1
1.0.0.1
198.41.0.4
64.233.160.0
208.67.222.222:8080
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression