re = /^([1-9]\d{0,3}|1\d{4}|20000)$/m
str = '50001
10000
1
10
100
1000
10000
19999
20000
20001'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html